Question

Drag the tiles to the boxes to form correct pairs.Match each trinomial to its factored form.

Answer 1

For the given question, we will match each trinomial to its factored form.

So, we will factor each given trinomial:

$3y^2-2y-8$

The factors of the trinomial will be:

$(y-2)(3y+4)$

And the second trinomial:

$3y^2+2y-8=(y+2)(3y-4)$

The third trinomial will be:

$3y^2-13y-10=(y-5)(3y+2)$

The fourth trinomial will be:

$3y^2+13y-10=(y+5)(3y-2)$