The sample is given
[tex]37.3055,37.4055,37.4673,37.3520,37.5109,37.3970,37.4819,37.2700,37.3763[/tex]First determine the mean of the sample,
The total number of masses are 9.
Then mean is calculated as sum of all the masses divided by total number of masses.
[tex]\frac{37.3055+37.4055+37.4673+37.3520+37.5109+37.3970+37.4819+37.2700+37.3763}{9}[/tex][tex]\frac{336.5614}{9}=37.39572[/tex]The mean obtained is 37.39572.
To determine the standard deviation , use the formula.
[tex]\sigma=\sqrt[]{\frac{1}{N}\Sigma(x_i-\mu)^2}[/tex]Now we have to evaluate the value of summation in the square root.
Now substitute the value in standard deviation formula
[tex]\sigma=\sqrt[]{\frac{1}{9}(0.0520756928)}=\sqrt[]{0.0057861880888}=0.076066997[/tex]Hence the standard deviation of the masses given is 0.076066997.