Respuesta :

the given expression is,

[tex]-\frac{25x^3y^3}{14a^2b}\times(-\frac{21ab}{10x^2y})[/tex]

now we solve it,

[tex]=\frac{25x^3y^3}{10x^2y}\times\frac{21ab}{14a^2b}[/tex][tex]=\frac{5x^{3-2}y^{3-1}}{2}\times\frac{21}{14a^{2-1}}[/tex][tex]=\frac{105xy^2}{28a}[/tex]

thus,, the answer is 105xy^2 / 28a

ACCESS MORE
EDU ACCESS