Respuesta :

we have the following:

We can solve the question by a system of equations, like this

let x, number of dime = $0.10

let y, number of quarter = $0.25

[tex]\begin{gathered} x+y=104\rightarrow x=104-y \\ 0.10x+0.25y=14 \\ 0.10\cdot(104-y)+0.25y=14 \\ 10.4-0.1y+0.25y=14 \\ 0.15y=14-10.4 \\ y=\frac{3.6}{0.15}=24 \end{gathered}[/tex]

now, for x:

[tex]\begin{gathered} x=104-24 \\ x=80 \end{gathered}[/tex]

therefore, there are 24 quarters and 80 dimes, in total 104 coins and represent $14

RELAXING NOICE
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