Hey could I get sum assistance with this learning exercise sand a brief explanation, thanks

The rule of the sum of n terms in the arithmetic sequence is
[tex]S_n=\frac{n}{2}[2a+(n-1)d][/tex]a is the 1st term
d is the common difference
n is the number of the terms
The given sequence is
[tex]9,14,19,24,29,34,.....[/tex]Since
[tex]\begin{gathered} 14-9=5 \\ 19-14=5 \\ 24-19=5 \end{gathered}[/tex]Then the common difference is 5
d = 5
Since the 1st term is 9, then
a = 9
Since we need to find the sum of 23 terms, then
n = 23
Substitute these values in the rule above
[tex]\begin{gathered} S_{23}=\frac{23}{2}[2(9)+(23-1)(5)] \\ \\ S_{23}=\frac{23}{2}[18+110] \\ \\ S_{23}=\frac{23}{2}[128] \\ \\ S_{23}=1472 \end{gathered}[/tex]The sum of the first 23 terms is 1472
The answer is d