Respuesta :

The rule of the sum of n terms in the arithmetic sequence is

[tex]S_n=\frac{n}{2}[2a+(n-1)d][/tex]

a is the 1st term

d is the common difference

n is the number of the terms

The given sequence is

[tex]9,14,19,24,29,34,.....[/tex]

Since

[tex]\begin{gathered} 14-9=5 \\ 19-14=5 \\ 24-19=5 \end{gathered}[/tex]

Then the common difference is 5

d = 5

Since the 1st term is 9, then

a = 9

Since we need to find the sum of 23 terms, then

n = 23

Substitute these values in the rule above

[tex]\begin{gathered} S_{23}=\frac{23}{2}[2(9)+(23-1)(5)] \\ \\ S_{23}=\frac{23}{2}[18+110] \\ \\ S_{23}=\frac{23}{2}[128] \\ \\ S_{23}=1472 \end{gathered}[/tex]

The sum of the first 23 terms is 1472

The answer is d

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