Question

2. A school club sold children's and adults' tickets to a fundraiser. Children'stickets sold for $3.50 each, and adults' tickets sold for $7.50 each. Theclub sold a total of 62 tickets and collected a total of $365.00. How manychildren's tickets were sold?C37A 19D. 42B. 25

Answer 1

Solution:

Given:

Let x represent children tickets

Let y represent adult tickets

Hence,

$\begin{gathered} Total\text{ of 62 tickets sold means;} \\ x+y=62 \\ \\ \\ Total\text{ c}ost\text{ of children ticket is \ }3.50x \\ Total\text{ }cost\text{ of adult ticket is \ }7.50y \\ \\ Total\text{ tickets sold cost \ 365.00. This means;} \\ 3.5x+7.5y=365 \end{gathered}$

Solving the two equations simultaneously;

$\begin{gathered} x+y=62.............................(1) \\ 3.5x+7.5y=365..........................(2) \\ \\ From\text{ \lparen1\rparen,} \\ y=62-x \\ \\ Substitute\text{ y into equation \lparen2\rparen;} \\ 3.5x+7.5(62-x)=365 \\ 3.5x+465-7.5x=365 \\ 465-365=7.5x-3.5x \\ 100=4x \\ \frac{100}{4}=x \\ x=25 \\ \\ 25+y=62 \\ y=62-25 \\ y=37 \end{gathered}$

x = children tickets = 25

y = adult tickets = 37

Therefore, 25 children tickets were sold.