Given:
[tex]1-sin^2x[/tex]Solution
Recall that from trigonometric identities:
[tex]\sin ^2x+cos^2x\text{ = 1}[/tex]Re-arranging, we have:
[tex]\cos ^2x=1-sin^2x[/tex]Hence,
[tex]\begin{gathered} 1-sin^2x=cos^2x \\ \text{Answer : cos}^2x \end{gathered}[/tex]