[tex]\begin{gathered} C=(F-32)\frac{5}{9}=\frac{(F-32)}{1.8} \\ F=1.8C+32 \\ K=C+273 \\ \text{First, we must convert F into C, hence, when F=77 one has} \\ \end{gathered}[/tex][tex]\begin{gathered} C=(77-32)\frac{5}{9} \\ C=45\frac{5}{9} \\ C=\frac{45\cdot5}{9} \\ C=\frac{5\cdot9\cdot5}{9} \\ C=5\cdot5 \\ C=25\text{ } \end{gathered}[/tex][tex]\begin{gathered} \text{Now, we must convert celsius to kelvin:} \\ K=25+273 \\ K=298 \end{gathered}[/tex]
