Question

There is a spinner with 8 equal areas, numbered 1 through 8. If the spinner is spunone time, what is the probability that the result is a multiple of 2 and a multiple of 3?

Answer 1

Since the total sections of the spinner are 8

Since the numbers on sections from 1 to 8

1, 2, 3, 4, 5, 6, 7, 8

The multiples of 2 are: 2, 4, 6, 8

Then the probability of multiples of 2 is

$P(M.2)=\frac{4}{8}=\frac{1}{2}$

The multiples of 3 are: 3, 6

Then the probability of multiples of 3 is

$P(M.3)=\frac{2}{8}=\frac{1}{4}$

Since we need both, then

$P(M.2\cap M.3)=\frac{1}{2}\times\frac{1}{4}=\frac{1}{8}$

The answer is 1/8