Question

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B^2 to both sides of the equation in step 4, what is the constant on the right side of the equation? a. -32b. 112c. 160

Answer 1

1. Write the equation in the form:

$Ax^2+Bx+C=0$

$2x^2+8x-12=0$

You indentify A is 2 and B is 8 in the given equation:

$A=2$$B=8$

2. 4A is 8 (4*2=8):

$8\lbrack2x^2+8x-12\rbrack=8\lbrack0\rbrack$

$16x^2+64x-96=0$

3.

$16x^2+64x=96$

4. B^2 is 64 (8*8=64)

$\lbrack16x^2+64x\rbrack+64=\lbrack96\rbrack+64$$16x^2+64x+64=160$After step 4, the constant on the right side of the equation is 160