[tex]\begin{gathered} \text{Given} \\ \sum_{i=2}^4k(k-11) \end{gathered}[/tex][tex]\begin{gathered} \operatorname{\sum}_{\imaginaryI=2}^4^k(k-11) \\ =2(2-11)+3(3-11)+4(4-11) \\ =2(-9)+3(-8)+4(-7) \\ =-18-24-28 \\ =-70 \end{gathered}[/tex]
Therefore
[tex]\sum_{i=2}^4k(k-11)=-70[/tex]
