EXPLANATION
Given the syhstem o equations:
(1) 2x -3y = -6
(2) x + 5y = 23
Isolate x for 2x -3y = -6
Add 3y to both sides:
2x -3y +3y = -6 + 3y
Simplify:
2x = -6 + 3y
Divide both sides by 2:
2x/2 = -6/2 + 3y/2
Simplify:
x= (-6+3y)/2
Substitute x=(-6+3y)/2
[(-6+3y)/2 + 5y = 23]
Simplify:
[(-6+13y)/2 = 23]
Isolate y for (-6+13y)/2 =23
Multiply both sides by 2:
[2(-6+13y)/2]=23*2
Simplify:
-6 + 13y = 46
Add 6 to both sides:
-6 + 13y + 6 = 46 + 6
Simplify:
13y = 52
Divide both sides by 13:
13y/13 = 52/13
Simplify:
y = 4
For x = (-6+3y)/2
Substitute y=4
x=(-6+3*4)/2
Simplifying:
x = 6/2
Divide the numbers 6/2 = 3
x=3
The solutions to the system of equations are:
x=3, y=4
