19)
Given data:
The given polynomial is
[tex]x^3-5x^2-8x+8^{}[/tex]
Substitute -2 for x in the above polynomial.
[tex]\begin{gathered} (-2)^3-5(-2)^2-8(-2)+8 \\ =-8-20+16+8 \\ =-4 \end{gathered}[/tex]
As after substituting x=-2 in the polymial is not equal to zero.
Thus, (x+2) is not the factor of the polynomial
