Question

An ice block on a frictionless path starts at rest and is released on the path. How much KE does it have at point B?

Answer 1

The difference in the height at which the ice block starts its motion to the height of the point B is,

$\begin{gathered} h=4.5-2 \\ h=2.5\text{ m} \end{gathered}$

The kinetic energy at the point B in terms of the potential energy for this difference in height is,

$K=\text{mgh}$

Substituting the known values,

$\begin{gathered} K=m\times9.8\times2.5 \\ K=24.5\text{m} \end{gathered}$

where m is the mass of the ice block.

Thus, the value of the kinetic energy at the point B is 24.5m.