Given the following inequality:
[tex]5x-y\leqslant10[/tex]
To graph the inequality, first, we need to graph the line: 5x - y = 10
Using the intercepts of the line
when x = 0, y = -10
When y = 0, x = 2
So, the line passes through the points (0, -10) and (2, 0)
the line will be solid because of the sign ≤
Now, we will use the point (0, 0) as a test point to decide which area will be the solution to the given inequality
so, when x = 0, and y = 0
[tex]0\leqslant10[/tex]
which is a true condition
So, the answer will be:
