Question

What is the magnetic field if a force of 1.38N is experienced by a 6.12C charge traveling at 7.82m/s?34.7T0.0288T0.567T1.76T

Answer 1

We can find the magnetic field as follows:

$\begin{gathered} B=\frac{F}{qv} \\ where: \\ q=6.12C \\ v=7.82m/s \\ F=1.38N \\ Therefore: \\ B=\frac{1.38}{6.12\cdot7.82}=\frac{1.38}{47.8584} \\ B=0.0288T \end{gathered}$

Answer:

0.0288 T