Answer
36, 12, 4, (4/3), (4/9), (4/27)
Explanation
Geometric sequence is one in which each term is obtained by multiplying or dividing a constant to the preceding term.
The nth term of a geometric sequence is given as
aₙ = a rⁿ⁻¹
[tex]a_n=a(r^{n-1})[/tex]where
a = first term = 36
n = number of terms
r = common ratio = (Second term)/(First term) = (Third term)/(Second term)
r = (12/36) = (4/12) = ⅓
So, we can find the next three terms.
Fourth term,
a = 36
n = 4
r = ⅓
[tex]\begin{gathered} a_n=a(r^{n-1}) \\ a_4=36\lbrack(\frac{1}{3})^{4-1}\rbrack \\ a_4=36\lbrack(\frac{1}{3})^3\rbrack \\ a_4=36(\frac{1}{27})=\frac{36}{27}=\frac{4}{3} \end{gathered}[/tex]For the fifth and sixth term, we can just keep multiplying by the common ratio, ⅓
Fourth term = (4/3)
Fifth term = (4/3) × (1/3) = (4/9)
Sixth term = (4/9) × (1/3) = (4/27)
Hope this Helps!!!