the measure of the angle from least to greatest
Explanation:
B(0, 6)
C(2. -5)
D(-8, -1)
Plotting the points on a graph:
To determine the angles from the least to the greatest, we need to find the distance between the points.
distance formula:
[tex]dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} \text{Distance BC = }\sqrt[]{(-5_{}-6)^2+(2_{}-0)^2} \\ =\text{ }\sqrt[]{(-11)^2+(2)^2}\text{ = }\sqrt[]{121\text{ + 4}}\text{ = }\sqrt[]{125\text{ }} \\ \text{Distance BC = 1}1.18 \end{gathered}[/tex][tex]\begin{gathered} x_1=2,y_1=-5,x_2=-8,y_2\text{ = -1} \\ \text{Distance CD = }\sqrt[]{(-1-(_{}-5))^2+(-8_{}-2)^2} \\ \text{Distance CD = }\sqrt[]{(-1+5)^2+\mleft(-10\mright)^2} \\ =\text{ }\sqrt[]{(4)^2+100}\text{ = }\sqrt[]{116} \\ \text{Distance CD = 10.77} \end{gathered}[/tex][tex]\begin{gathered} x_1=0,y_1=6,x_2=-8,y_2\text{ = -1} \\ \text{Distance BD = }\sqrt[]{(-1-_{}6)^2+(-8_{}-0)^2} \\ =\sqrt[]{(-7)^2+(-8)^2\text{ }}\text{ = }\sqrt[]{49\text{ + 64}}\text{ = }\sqrt[]{113} \\ \text{Distance BD= }10.63 \end{gathered}[/tex]
The higher the length, the higher the angle
BC > CD and CD > BD
From the least to the greatest, the distance between the points are:
BD, CD, BC
The angles are opposite the distance and corresponds to each other
Following the arrangement of the distance,
Hence, the measure of the angle from least to greatest
