Question

The fifth term of the sequence 1 /(n^2+1) is:

Answer 1

The general term of a sequence is given as:

$a_n=\frac{1}{n^2+1}$

Where n is the number of the term, starting from n = 1.

It's required to find the fifth term of the sequence, that is, for n = 5. Substitute:

$a_5=\frac{1}{5^2+1}$

Calculating:

$\begin{gathered} a_5=\frac{1}{25+1} \\ a_5=\frac{1}{26} \end{gathered}$

The fifth term is 1/26