Question

A rectangular fountain has a length of g meters and a width 3 meters less than it's length. how much does it cost to border the outside of the fountain using 1- meter tiles that cost $4 each?

Answer 1

Let g be the length of the rectangle; thus, its width is g-3.

Then, the perimeter of the rectangle is

$\begin{gathered} P=g+g+(g-3)+(g-3) \\ \Rightarrow P=4g-6 \end{gathered}$

Where P is in meters

Therefore, the cost of bordering the outside of the fountain is

$\begin{gathered} \cos t=4P=4(4g-6)=16g-24 \\ \Rightarrow\text{ cost}=16g-24 \end{gathered}$

The total cost is equal to 16g-24