Respuesta :

We will investigtate the application of scale factors to re-size any image or figure.

The figure at hand is described as a triangle. Every triangle has two distinct side lengths namely:

[tex]\text{Height \& Base}[/tex]

The original side-length for each of the distinct sides is given as follows:

[tex]\begin{gathered} \text{Height : 24 cm} \\ \text{Base : 32 cm} \end{gathered}[/tex]

We are to re-size the original triangle as per the scale factor given:

[tex]\text{Scale Factor = }\frac{1}{4}[/tex]

A general rule for re-sizing any figure either enlarging or shrinking can be given by the numerical value of scale factor as follows:

[tex]\begin{gathered} \text{Scale Factor > 1 }\ldots\text{ Enlargement} \\ \text{Scale Factor = 1 }\ldots\text{ Actual/Original} \\ \text{Scale Factor < 1 }\ldots\text{ Shrinking/Reduction} \end{gathered}[/tex]

The scale factor given is expressed as a fraction (1/4). This lies in the third category. Hence, we will be reducing the size of the original triangle.

By re-sizing any figure we apply the scale factor to every distinct side-length of the figure. For the case of triangle these side lengths are base and height. The general formulation used while re-sizing is:

[tex]\operatorname{Re}-\text{sized length = Scale Factor }\cdot\text{ Original length}[/tex]

We will use the above relation for each of the side-lengths of a triangle as follows:

[tex]\begin{gathered} \text{Reduced Height = }\frac{1}{4}\cdot24 \\ \\ \text{Reduced Height = 6 cm} \end{gathered}[/tex][tex]\begin{gathered} \text{Reduced Base = }\frac{1}{4}\cdot32 \\ \\ \text{Reduced Base = 8 cm} \end{gathered}[/tex]

Therefore the base of the reduced triangle would be:

[tex]8\text{ cm}[/tex]

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