Answer:
[tex]-3c-b=\frac{8}{15}[/tex]
Explanation:
We have:
[tex]\begin{gathered} b=\frac{2}{3} \\ c=-\frac{2}{5} \end{gathered}[/tex]The expression is:
[tex]-3c-b[/tex]To evaluate, we replace the given values of b and c in the expression:
[tex]-3\cdot(-\frac{2}{5})-\frac{2}{3}[/tex]And solve:
[tex]3\cdot\frac{2}{5}-\frac{2}{3}[/tex][tex]\frac{6}{5}-\frac{2}{3}[/tex]The least common multiply of 3 and 5 is 3 * 5 = 15. Then:
[tex]\frac{6\cdot3}{5\cdot3}-\frac{2\cdot5}{3\cdot5}=\frac{18}{15}-\frac{10}{15}[/tex]
Now we can rest the numerators:
[tex]\frac{18}{15}-\frac{10}{15}=\frac{8}{15}[/tex]And that's the answer
