Given: The system of equations below
[tex]\begin{gathered} y=-x+4 \\ x-3y=12 \end{gathered}[/tex]To Determine: The solution of the system of equations
Solution
Let us combine the two equations
[tex]\begin{gathered} equation1:y=-x+4 \\ equation2:x-3y=12 \end{gathered}[/tex]Substituting equation 1 into equation 2
[tex]\begin{gathered} x-3(-x+4)=12 \\ x+3x-12=12 \\ 4x=12+12 \\ 4x=24 \\ x=\frac{24}{4} \\ x=6 \end{gathered}[/tex]Substitute x = 6 into equation 1
[tex]\begin{gathered} y=-x+4 \\ y=-6+4 \\ y=-2 \end{gathered}[/tex]Hence, the solution is (6, -2)