11:20 Mathematics 5 points Graph the line that passes through the points (3, -6) and (-6, -3) and determine he equation of the line. timswife · Helping Handcan you show me how to graphthis

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The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The line passes through the points (3, -6) and (-6, -3), its slope is:

[tex]m=\frac{-3-(-6)}{-6-3}=\frac{3}{-9}=-\frac{1}{3}[/tex]

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

Substituting with m = -1/3 and the point (3, -6), we get:

[tex]\begin{gathered} -6=-\frac{1}{3}\cdot3+b \\ -6=-1+b \\ -6+1=b \\ -5=b \end{gathered}[/tex]

The equation is:

y = -1/3x - 5

To graph a line, you need to find 2 points on it and connect them. Using the points (3, -6) and (-6, -3), we get:

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