Answer:
[tex]\begin{gathered} \text{ A tray of club sandwiches cost \$9} \\ A\text{ tray of vegetarian sandwiches cost \$6.} \end{gathered}[/tex]Step-by-step explanation:
Given the information, create the following augmented matrix:
The first order was for 1 tray of club sandwiches, at a cost of $9. The second-order, which cost $69, was for 5 trays of club sandwiches and 4 trays of vegetarian sandwiches.
[tex]\begin{gathered} 5x+4y=69 \\ x=9 \end{gathered}[/tex]Into an augmented matrix:
[tex]\begin{bmatrix}{5} & {4} \\ {\placeholder{⬚}} & {1}\end{bmatrix}\begin{bmatrix}{69} & {} \\ {9} & {}\end{bmatrix}[/tex]Solve.
Let x be the cost of a tray of club sandwiches.
Let y be the cost of a tray of vegetarian sandwiches.
[tex]\begin{gathered} x=9 \\ Substitute\text{ on the first equation} \\ 5(9)+4y=69 \\ 4y=69-45 \\ y=\frac{24}{4} \\ y=6 \end{gathered}[/tex]