Question

15)The trajectory of a lacrosse ball thrown from a stick is given by the equation h=-16 + 110t + 7a) What is the starting height of the ball in its trajectory?b) What is the original upward velocity of the ball in its trajectory?

Answer 1

Solution

- The general formula for the trajectory of a projectile is given below:

$\begin{gathered} H(t)=at^2+vt+h \\ where \\ v=initial\text{ velocity of the projectile} \\ h=initial\text{ }height \end{gathered}$

- Comparing this with the equation given, we have:

$\begin{gathered} H=-16t^2+110t+7 \\ H=at^2+vt+h \\ \\ \text{ We have:} \\ v=110,h=7 \end{gathered}$

Final Answer

Starting Height (h) = 7

Initial velocity (v) = 110