Question

44. Write an equation of a circle in standard form given the center is (-1, -2) and a radius of 4.

Answer 1

Answer: d.

$(x+1)^{2}+(y+2)^{2}=16$

Explanation

• The standard form of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

where (h, k) is the center and r is the radius.

In our case, we are told that the center is (–1, –2) and the radius is 4. Thus:

• h = –1

,

• k = –2

,

• r = 4

Then, we can replace these values in the standard form of a circle and simplify:

$(x-(-1))^2+(y-(-2))^2=(4)^2$$(x+1)^2+(y+2)^2=16$