Question

Calculate the current produced for a lightbulb with 1.0 x105 C of charge passing through a filament for 2.5 hours.

Answer 1

Given,

The charge passed through the filament, q=1.0×10⁵ C

The time duration, t=2.5 hrs

To convert the time duration from hours to seconds,

$\begin{gathered} t=2.5\times3600 \\ =9000\text{ s} \end{gathered}$

The electric current is the time rate at which the electric charges flow.

Thus the current produced is given by,

$I=\frac{q}{t}$

On substituting the known values,

$\begin{gathered} I=\frac{1.0\times10^5}{9000} \\ =11.11\text{ A} \end{gathered}$

Thus, the current produced is 11.11 A