Given
y varies inversely with x. y= 12 when x = 4
Answer
[tex]\begin{gathered} y\propto\frac{1}{x} \\ y=\frac{k}{x}\ldots\text{.}\mathrm{}(1) \\ y=12,x=4 \\ 12=\frac{k}{4} \\ k=48 \\ \text{ use in 1} \\ y=\frac{48}{x} \\ \text{ use x = -6} \\ y=\frac{48}{-6} \\ y=-8 \end{gathered}[/tex]
