Question

7(x-2)-3(x+3)=5(x-3)+x

Answer 1

Given:-

$7\mleft(x-2\mright)-3\mleft(x+3\mright)=5\mleft(x-3\mright)+x$

To find the value of x.

So now we simplify,

$\begin{gathered} 7(x-2)-3(x+3)=5(x-3)+x \\ 7x-14-3x-9=5x-15+x \\ 4x-25=6x-15 \\ 4x-6x=-15+25 \\ -2x=10 \\ x=-\frac{10}{2} \\ x=-5 \end{gathered}$

So the required value is -5.