Question

What is the midpoint of the horizontal line segment graphed below?10(-6,3)(10,3)10A. (2,6)В. (4, 6)ОООC. (2, 3)D. (4, 3)

Answer 1

$(x_m,y_m)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Therefore,

(-6, 3)(10, 3)

$\begin{gathered} (x_m,y_m)=(\frac{-6+10}{2},\frac{3+3}{2}) \\ (x_m,y_m)=(\frac{4}{2},\frac{6}{2}) \\ (x_m,y_m)=(2,3) \end{gathered}$