So the initial equation is:
[tex]8x^2+8x=-2[/tex]To writte the equation in the standard form we have to make it equal to 0, so we can add 2 in bout sides of the equation:
[tex]\begin{gathered} 8x^2+8x+2=-2+2 \\ 8x^2+8x+2=0 \end{gathered}[/tex]now, (a) is the number thas goes with the x^2, (b) is the number that goes with the x and (c) is the number that is alon, so:
[tex]\begin{gathered} a=8 \\ b=8 \\ c=2 \end{gathered}[/tex]Now we can substitute this numbers in the quadratic equation:
[tex]\begin{gathered} \frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \frac{-8\pm\sqrt[]{8^2-4(8)(2)}}{2(8)} \end{gathered}[/tex]and finally we can simplify the equation:
[tex]\begin{gathered} \frac{-8\pm\sqrt[]{64-64}}{16} \\ \frac{-8}{16}=\frac{-4}{8}=\frac{-2}{4}=-\frac{1}{2} \end{gathered}[/tex]