x = -CD/CD2-40 DC8x2 + 8x = -2Write the quadratic equation in standard form:( a )x2 + ( b )x+ C) = 0Identify the values of a, b, and c.b =Substitute these values into the quadratic formula and simplify:2( )a =C=

Respuesta :

So the initial equation is:

[tex]8x^2+8x=-2[/tex]

To writte the equation in the standard form we have to make it equal to 0, so we can add 2 in bout sides of the equation:

[tex]\begin{gathered} 8x^2+8x+2=-2+2 \\ 8x^2+8x+2=0 \end{gathered}[/tex]

now, (a) is the number thas goes with the x^2, (b) is the number that goes with the x and (c) is the number that is alon, so:

[tex]\begin{gathered} a=8 \\ b=8 \\ c=2 \end{gathered}[/tex]

Now we can substitute this numbers in the quadratic equation:

[tex]\begin{gathered} \frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \frac{-8\pm\sqrt[]{8^2-4(8)(2)}}{2(8)} \end{gathered}[/tex]

and finally we can simplify the equation:

[tex]\begin{gathered} \frac{-8\pm\sqrt[]{64-64}}{16} \\ \frac{-8}{16}=\frac{-4}{8}=\frac{-2}{4}=-\frac{1}{2} \end{gathered}[/tex]

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