If x2 = 40, what is the value of x?+80O +20O V80O V40

To solve this, you need to make this
Step 1
square root in both sides
[tex]\begin{gathered} x^2=40 \\ \sqrt{x^2}=\sqrt{40} \\ \text{the }\sqrt{\square}\text{ is eliminated by the exponent} \\ x=\sqrt{40} \end{gathered}[/tex]Now, the two solutions for this are.
[tex]\begin{gathered} x=\sqrt{40} \\ x=-\sqrt{40} \\ \\ \end{gathered}[/tex]so, the answer is
[tex]x=\pm\sqrt{40}[/tex]I hope it helps you.