Question

Forty ounces of Lazy Lawn fertilizer covers 1,250 square feet of lawn.(a)How many ounces would be required to cover a 9,000 square foot lawn? ounces(b)If Lazy Lawn costs $1.11 for a 36 ounce bag, what is the total cost (in dollars) to fertilize the lawn?$

Answer 1

(a) Given that 40 ounces of Lazy Lawn fertilizer cover 1,250 square feet of lawn, let be "x" the number of ounces that would be required to cover a 9,000 square foot law.

You can set up the following proportion:

$\frac{40}{1250}=\frac{x}{9000}$

Now you need to solve for "x", in order to find its value:

$(9000)(\frac{40}{1250})=x$$x=288$

(b) You know that Lazy Lawn costs $1.11 for a 36-ounce bag.

Let be "c" the total cost (in dollars) to fertilize the 9,000 square-foot lawn.

Knowing that 288 ounces are required to cover that lawn, you can set up this proportion:

$\frac{1.11}{36}=\frac{c}{288}$

Solving for "c", you get:

$(288)(\frac{1.11}{36})=c$$c=8.88$

Hence, the answers are:

(a)

$288\text{ }ounces$

(b)

$\text{ \ }8.88$