What’s the question this is hard I haven’t been teaches this

We know that a linear equation is given generally as:
y = mx + c
where m = gradient
and c = y intercept
We can see from the scatter plot that the y intercept is 1.12
So, already we have limited our options to B and C.
Now let us find our slope with the second and third data points:
(1, 1.15) and (2, 1.18)
Slope is given as:
[tex]m\text{ = }\frac{P_{2\text{ }}-P_1}{t_{2\text{ }}-t_1}[/tex][tex]m\text{ = }\frac{1.18\text{ - 1.15}}{2\text{ - 1}}[/tex][tex]m\text{ = }\frac{0.03}{1}[/tex]m = 0.03
Which means that if we were to write a linear equation of this, it would be:
P(t) = 0.03t + 1.12
The only option that is close to this is B which is:
P(t) = 0.02t + 1.12
Hence, this is our answer.