Given that Triangle ACE - Triangle IKS, find the value of y.

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
Therefore we have,
[tex]\frac{EC}{KS}=\frac{AC}{IK}[/tex]Substituting the values, we have,
[tex]\begin{gathered} \frac{12}{4}=\frac{y}{3.2} \\ 3=\frac{y}{3.2} \\ y=9.6 \end{gathered}[/tex]Thus, the value of y is 9.6