Question

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol, the molar mass of S is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. What is the molarity of the solution?A.0.1400 kg/LB.0.8771 mol/LC.0.8823 mol/kgD.2.538 g/mol

Answer 1

The molarity is calculated using the following formula:

$C\text{ = }\frac{\text{moles of solute}}{\text{Volume of solution}}$

We need to first find the number of moles of CuSO4. The mass = 35.00g and molar mass = (63.55 + 32.07 + (16x4) = 159.62 g/mol. Volume of the solution = 250.0 mL = 0.250 L

n = m/M

n = 35.00 g/159.62 g/mol

n = 0.219 mol

C = 0.219 mol/0.250 L

C = 0.8771 mol/L

Therefore the answer is B.