Question

how many solutions does the system have 2x+ 3y=-3 and 3xbravo+5y=-9

Answer 1

Solution

We have the following two equations given:

2x + 3y = -3

We can solve for x and we got:

$x=\frac{-3-3y}{2}$

We can replace into the second equation and we got:

$3(\frac{-3-3y}{2})+5y=-9$

And solving for y we got:

$-\frac{9}{2}-\frac{9}{2}y+5y=-9$

then the value of y would be:

$y=2\cdot(-\frac{9}{2})=-9$

And solving for x we got:

$x=\frac{-3-3(-9)}{2}=12$