A normal distribution has a mean of 36 and a standard deviation of 4. Find the probability thata randomly selected x-value from the distribution is in the given interval20242832 36404448 529%Enter an integer or decimal number [more..]to d

Answer:
Explanation:
Given:
mean = 36
standard deviation = 4
To find:
the probability that a randomly selected x-value from the distribution is in the given interval 32 and 40