Question

Write the first six terms of the sequence? begin at n=1.

Answer 1

Explanation:

Consider the following sequence:

$a_n=a(n)=2n\text{ -1}$

If we evaluate this sequence for each first six natural numbers (starting from 1), we get the following:

for n= 1

$a_{1\text{ }}=a(1)\text{ = 2\lparen1\rparen-1 = 2-1 = 1}$

for n= 2

$a_2=\text{ a\lparen2\rparen= 2\lparen2\rparen-1 = 4-1 = 3}$

for n = 3:

$a_3=\text{ a\lparen3\rparen= 2\lparen3\rparen-1 = 6-1 = 5}$

for n= 4:

$a_4=\text{ a\lparen4\rparen=2\lparen4\rparen-1 = 8-1 = 7}$

for n= 5:

$a_5=\text{ a\lparen5\rparen=2\lparen5\rparen-1 = 10-1 = 9}$

and for n= 6:

$a_{6\text{ }}=\text{ a\lparen6\rparen= 2\lparen6\rparen-1 = 12-1 = 11}$

we can conclude that the correct answer is:

Answer:

$a_{1\text{ }}=\text{ 1}$

$a_2=\text{ 3}$

$a_3=\text{ 5}$

$a_4=\text{ 7}$

$a_5=\text{ 9}$

$a_{6\text{ }}=\text{ 11}$