For this case we need to describe the following transformation given:
[tex]-\frac{1}{2}f(x-3)-4[/tex]Let's take an example and look what happens. We can assume that our function is:
[tex]f(x)=x^2[/tex]If we apply the first part of the transformation we got:
[tex]f(x-3)=(x-3)^2[/tex]And for the total transformation we got:
[tex]-\frac{1}{2}f(x-3)-4=-\frac{1}{2}(x-3)^2-4[/tex]And as we can see our new function have a translation to the right of 3 units and 4 units down.
Since for this case we have a -1/2 at the begin of the equation we have the function rotated around the x axis