Question

2/3 (9-x)< 3=...What is the answer?

Answer 1

$\frac{2}{3}$

$\frac{2}{3} (9) - x \ \textless \ ?$ 

$\frac{2(9) - x}{3} - 3 \ \textless \ ?$

$\frac{3(3)}{3}$

$\frac{9 - 2(x)}{3}$ < ? 

First: Multiply the number 3 on your sides

Second: Multiply again but by negative 1 {-1}

You have to flip your inquality sign since we multiplied from a negative number

2(x) 9 > ? 

Third: Divide on each of your sides by the number 2

x - $\frac{9}{2}$ > ? 

Forth: Add the fraction of $\frac{9}{2}$ to the sides 

-.667 (3.0)  < ? 

Lets just say: 3.0 is a positve while -.667 is a negative 

Finally we get to your result 

Answer: $x \ \textgreater \ \frac{9}{2}$

Good Luck!