graph y= x² + 2x - 8. Then determine which answer choice matches the graph you drew. Find the x-intercepts.Identify the solution that has the correct graph and the correct x-intercepts.


ANSWER
Option A
EXPLANATION
First, we have to find the x-intercepts, so we have to solve,
[tex]x^2+2x-8=0[/tex]To do so, we can use the quadratic formula,
[tex]\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]In this case, a = 1, b = 2, and c = -8,
[tex]x=\frac{-2\pm\sqrt{2^2-4\cdot1\cdot(-8)}}{2\cdot1}=\frac{-2\pm\sqrt{4+32}}{2}=\frac{-2\pm\sqrt{36}}{2}=\frac{-2\pm6}{2}[/tex]So, the x-coordinates of the two x-intercepts are,
[tex]\begin{gathered} x=\frac{-2-6}{2}=\frac{-8}{2}=-4 \\ \\ x=\frac{-2+6}{2}=\frac{4}{2}=2 \end{gathered}[/tex]Hence, the x-intercepts are (-4, 0) and (2, 0), which reduces the graph options to two possibilities: graph A or graph C. Each has the x-coordinate of its vertex at each side of the y-axis: for graph A the x-coordinate of the vertex is negative, while for graph C it is positive.
To decide which one of these graphs is the correct one, we will find the x-coordinate of the vertex of the function, given by,
[tex]x_{vertex}=\frac{-b}{2a}[/tex]In this case, a = 1, and b = 2,
[tex]x_{vertex}=\frac{-2}{2\cdot1}=-1[/tex]Hence, the graph of this function is graph A.