A car starts from rest and accelerates uniformly for a distance of 160 m over an 8.0-second time interval. The car's acceleration is---

Respuesta :

Given:

The initial velocity of the car is

[tex]v_i=0\text{ m/s}[/tex]

The distance covered by the car is d = 160 m

The time duration is t = 8 s

Required: The car acceleration

Explanation:

The acceleration can be calculated by the formula

[tex]d=v_it+\frac{1}{2}at^2[/tex]

On substituting the values, the acceleration of the car will be

[tex]\begin{gathered} 160=0\times8+\frac{1}{2}a\times(8)^2 \\ 320=64a \\ a=5\text{ m/s}^2 \end{gathered}[/tex]

Final Answer: The car's acceleration is 5 m/s^2.

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