Question

Consider the equilibrium below: If 1.2 mol of H2 and 1.2 mol of I2 was placed in a 1.0 L container and allowed to reach equilibrium, what would the value of K be if at equilibrium [HI] = 0.40 mol/L? H2(g) + I2(g) ------>2HI(g) a)0.016 b)0.16 c)16 d) 1.6e) 0.0016

Answer 1

Answer

Equation of the reaction

H2 + O2 -----> 2HI(g)

From the equation, the equilibrium constant K can be calculated using

$K=\frac{\lbrack HI\rbrack^2}{\lbrack H\rbrack^2\lbrack O\rbrack^2}$

[HI] = 0.40 mol/L