A line includes the points (3,8) and (4,10). What is its equation in slope-intercept form? Write your answer using integers, proper fractions, and improper fractions in simplest form

The slope-intercept form of a line is:
[tex]y=mx+b[/tex]Where m is the slope of the line and b is the y-intercept.
As a middle step, we can use the slope-point form, which is:
[tex]y-y_1=m(x-x_1)[/tex]Where (x₁, y₁) is a point in the line.
The slope can be found by using both points:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, using the points we have, (3, 8) and (4, 10):
[tex]m=\frac{10-8}{4-3}=\frac{2}{1}=2[/tex]And the slope-point form:
[tex]y-8=2(x-3)[/tex]Now, we can just solve of y to get it to the slope-intercept form:
[tex]\begin{gathered} y-8=2(x-3) \\ y-8=2x-6 \\ y=2x-6+8 \\ y=2x+2 \end{gathered}[/tex]So, the slope-intercept equation is:
[tex]y=2x+2[/tex]