Question

i need help and the teacher isnt good at explaining

Answer 1

We are given the following equation

$y=mx+b$

We are also given the following values

$\begin{gathered} y=5 \\ m=\frac{1}{2} \\ x=4 \end{gathered}$

Let us substitute these values into the given equation and solve for b

$\begin{gathered} y=mx+b \\ 5=\frac{1}{2}\cdot4+b \\ 5=\frac{4}{2}+b \\ 5=2+b \\ 5-2=b \\ 3=b \\ b=3 \end{gathered}$

Therefore, the value of b is 3