Respuesta :

Using the long division we get:

Therefore:

[tex]\frac{c^3+5}{c+4}=c^2-4c+16-\frac{59}{c+4}.[/tex]

Answer:

[tex]\frac{c^3+5}{c+4}=c^2-4c+16-\frac{59}{c+4}.[/tex]

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