write the linear equation that demonstrates the relation in the table below.

First let's calculate the slope of the curve
A = (0, 3)
B = (1, 5)
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{5-3}{1-0} \\ m=\frac{2}{1} \\ m=2 \end{gathered}[/tex]Now let's calculate the intersection
[tex]\begin{gathered} b=y-mx \\ b=3-2\cdot(0) \\ b=3 \end{gathered}[/tex]The equation of the line that passes through the points is
[tex]y=2x+3[/tex]