3.
Given Column A:
[tex]\begin{gathered} \text{Column A = }\frac{1}{10^{100}} \\ \text{Column B = }\frac{1}{10^{99}} \end{gathered}[/tex]
Let's simplify both:
[tex]\text{Column A: }\frac{1}{10^{100}}\text{ = 1 }\ast\text{ 1}0^{-100\text{ }}[/tex][tex]\text{Column B: }\frac{1}{10^{99}}\text{ = 1 }\ast10^{-99}[/tex]
We can see that Column B is greater than column A.
ANSWER:
The quantity in column B is greater
